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Old 03-20-2014, 12:00 PM
smetz02 smetz02 is offline
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Default Native XML to ER7

Hi everyone,

I am brand new to Mirth and would like to know how to most easily transform an HL7 XML message, into ER7, pipe delimited format. There's an example of the XML format I'm using below, which has been truncated to exclude any PHI. This content is being delivered to a Channel with a Connector Type of Channel Reader. I would like to deliver this content to an LLP Sender Destination, in pipe-delimited format, without having to apply field by field mapping. Is there a way to just transform an entire XML message into it's equivalent ER7 format?

Thanks so much!

<ADT>
<MSH>
<MSH.1>|</MSH.1>
<MSH.2>^~\&amp;</MSH.2>
<MSH.7>
<TS.1>201402180920</TS.1>
</MSH.7>
<MSH.9>
<MSG.1>ADT</MSG.1>
<MSG.2>A08</MSG.2>
</MSH.9>
<MSH.10>48151</MSH.10>
<MSH.11>
<PT.1>T</PT.1>
</MSH.11>
<MSH.12>
<VID.1>2.3</VID.1>
</MSH.12>
</MSH>
....
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